7p^2=p^2-4p

Solution for 7p^2=p^2-4p equation:

7p^2=p^2-4p

We move all terms to the left:

7p^2-(p^2-4p)=0

We get rid of parentheses

7p^2-p^2+4p=0

We add all the numbers together, and all the variables

6p^2+4p=0

a = 6; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·6·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*6}=\frac{-8}{12}
=-2/3
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*6}=\frac{0}{12}
=0
$